M CUBE: Math-e-Matics by Maheshwari Basic Mathematics

In a right triangle ABC, right angled at B, BC = 15 cm, and AB = 8 cm. A circle is inscribed in triangle ABC. What is the radius of the circle?

We can directly use the formula r=Δ/s where r is the radius of in-circle, Δ is the area of the triangle and s is the semi-perimeter. Since its a right-angled triangle, we can use Pythagoras Theorem to find the third side.AC^2 = AB^2 + BC^2AC = 17 cm semi−perimeter = s = (AB+BC+CA)/2 = 20cm Δ = (base∗height)/2 = 60 sq.cm. … Continue reading In a right triangle ABC, right angled at B, BC = 15 cm, and AB = 8 cm. A circle is inscribed in triangle ABC. What is the radius of the circle?